Elimination of parity doubled states from Regge amplitudes

The common belief that fermions lying on linear Regge trajectories must have opposite-parity partners is shown to be false. The mechanism by which these experimentally nonexistant states are eliminated from the theory depends on the presence of fixed Regge cuts in fermion exchange amplitudes. Thus it is predicted that fermion Regge trajectories are always accompanied by fixed Regge cuts. More generally, if particles may be classified as composites of spin-1/2 (fermion) quarks, fixed cuts are expected to be present in boson exchange amplitudes as well. This result is demonstrated in the framework of the Van Hove model and a few further experimental consequences are discussed.