2 resultados para CONTAINMENT
em CaltechTHESIS
Resumo:
Zintl phases, a subset of intermetallic compounds characterized by covalently-bonded "sub-structures," surrounded by highly electropositive cations, exhibit precisely the characteristics desired for thermoelectric applications. The requirement that Zintl compounds satisfy the valence of anions through the formation of covalent substructures leads to many unique, complex crystal structures. Such complexity often leads to exceptionally low lattice thermal conductivity due to the containment of heat in low velocity optical modes in the phonon dispersion. To date, excellent thermoelectric properties have been demonstrated in several Zintl compounds. However, compared with the large number of known Zintl phases, very few have been investigated as thermoelectric materials.
From this pool of uninvestigated compounds, we selected a class of Zintl antimonides that share a common structural motif: anionic moieties resembling infinite chains of linked MSb4 tetrahedra, where $M$ is a triel element. The compounds discussed in this thesis (
Resumo:
If E and F are saturated formations, we say that E is strongly contained in F if for any solvable group G with E-subgroup, E, and F-subgroup, F, some conjugate of E is contained in F. In this paper, we investigate the problem of finding the formations which strongly contain a fixed saturated formation E.
Our main results are restricted to formations, E, such that E = {G|G/F(G) ϵT}, where T is a non-empty formation of solvable groups, and F(G) is the Fitting subgroup of G. If T consists only of the identity, then E=N, the class of nilpotent groups, and for any solvable group, G, the N-subgroups of G are the Carter subgroups of G.
We give a characterization of strong containment which depends only on the formations E, and F. From this characterization, we prove:
If T is a non-empty formation of solvable groups, E = {G|G/F(G) ϵT}, and E is strongly contained in F, then
(1) there is a formation V such that F = {G|G/F(G) ϵV}.
(2) If for each prime p, we assume that T does not contain the class, Sp’, of all solvable p’-groups, then either E = F, or F contains all solvable groups.
This solves the problem for the Carter subgroups.
We prove the following result to show that the hypothesis of (2) is not redundant:
If R = {G|G/F(G) ϵSr’}, then there are infinitely many formations which strongly contain R.