53 resultados para LANTHANIDES


Relevância:

10.00% 10.00%

Publicador:

Resumo:

Me4C2(C5H4MgCl)2(THF) (THF = tetrahydrofuran) reacts with anhydrous SmCl3 in THF to give [Me4C2CP2SMCl.THF]2. The molecule is a dimer. Sm1 and Sm2 are bridged unsymmetrically by two chlorine atoms [Sm(1)-CI(1) 2.787(2), Sm(1)-Cl(2) 2.848(2), Sm(2)-Cl(1) 2

Relevância:

10.00% 10.00%

Publicador:

Resumo:

The interaction of (C5H5)2SmCl.LiCl with one equivalent of Li[(CH2)(CH2) PPh2] in refluxing tetrahydrofuran gives the yellow complex [(C5H5)3SmCH2P (Me)Ph2] in 30% yield. The compound has been fully characterized by analytical, spectroscopic and X-ray diffraction methods.

Relevância:

10.00% 10.00%

Publicador:

Resumo:

[(Me4C2Cp2SmCl.MgCl2.3THF)THF]2 was prepared by the reaction of Me4C2Cp2MgCl2.4THF (Cp=C5H4, THF = tetrahydrofuran) with SmCl3 in THF. The crystals belong to triclinic space group P-1 with a 12.149(3), b 13.187(4), c 13.810(5) angstrom, alpha 117.23(2), beta 94.07(2), gamma 62.86(2)-degrees, V = 1723.9(1.0) angstrom3. In the molecular structure of the title compound there is a symmetrical centre and a quadrilateral formed by SM, Mg, Cl1, Cl2 atoms. Two centroids of the cyclopentadienyls, bridged by a tetramethylethano group form with three bridging chlorine atoms (Cl1, Cl2, Cl1a) a pseudo-trigonal bipyramid around Sm. Three oxygen atoms of THF and three chlorine atoMS (Cl1, Cl2, Cl3) constitute a distorted octahedron around Mg.

Relevância:

10.00% 10.00%

Publicador:

Resumo:

(ButCp)2NdCl.2THF reacts with one equivalent of phenyllithum in THF yielding tris(tert-butylcyclopentadienyl)neodymium lithium bromide tetrahydrofuran, [(ButCP)3 NdBrLi(THF)3], as a by-product, whose structure has been determined by X-ray crystallography. The 10-coordinated neodymium atom is bonded to three tert-butyl-cyclopentadienyl groups and one bromine atom, forming a distorted pseudo-tetrahedron.

Relevância:

10.00% 10.00%

Publicador:

Resumo:

SmCl3 reacts with K2C8H8 to yield the complex Sm(C8H8)Cl.2thf, which reacts with K(2,4-C7H11) (2,4-C7H11 = 2,4-dimethylcyclopentadienyl) to form Sm(C8H8)(2,4-C7H11).thf; the X-ray crystal structure of Sm(C8H8)(2,4-C7H11).thf shows that the 2,4-dimethylcyclopentadienyl has a 'U' conformation.

Relevância:

10.00% 10.00%

Publicador:

Resumo:

LnCL3 reacts with NaC5H5 and K2C8H8 to yield the complexes (eta-5-C5H5)Ln(eta-8-C8H8).nTHF (Ln = Pr, Nd, n = 2; Ln = Gd, n = 1) and LnCl3 reacts with KC9H7 and K2C8H8 to yield the complexes (eta-5-C9H7)Ln(eta-8-C8H8).2THF (Ln = Pr, Nd; eta-5-C9H7 = indenyl); crystallography reveals (eta-5-C5H5)Pr(eta-8-C8H8).2THF and (eta-5-C9H7)Pr(eta-8-C8H8).2THF not to possess the parallel ring sandwich structure.

Relevância:

10.00% 10.00%

Publicador:

Resumo:

The phenyl derivatives of lanthanides Sc(C_6H_5)_3, Y(C_6H_5)_3, LiLa (C_6H_5)_4 and LiPr(C_6H_5)_4 were prepared by Hart et al. in 1970, and dis(cyclopentadienyl) phenyl complexes of lanthanides have been isolated recently. We reported here the synthesis and crystallography parameters of a new type of phenyl derivative of neodymium: