Spin-state splittings, highest-occupied-molecular-orbital and lowest-unoccupied-molecular-orbital energies, and chemical hardness.


Autoria(s): Johnson, ER; Yang, W; Davidson, ER
Data(s)

28/10/2010

Identificador

http://www.ncbi.nlm.nih.gov/pubmed/21033775

J Chem Phys, 2010, 133 (16), pp. 164107 - ?

http://hdl.handle.net/10161/3345

1089-7690

http://hdl.handle.net/10161/3345

Idioma(s)

ENG

en_US

Relação

J Chem Phys

10.1063/1.3497190

Journal of Chemical Physics

Tipo

Journal Article

Cobertura

United States

Resumo

It is known that the exact density functional must give ground-state energies that are piecewise linear as a function of electron number. In this work we prove that this is also true for the lowest-energy excited states of different spin or spatial symmetry. This has three important consequences for chemical applications: the ground state of a molecule must correspond to the state with the maximum highest-occupied-molecular-orbital energy, minimum lowest-unoccupied-molecular-orbital energy, and maximum chemical hardness. The beryllium, carbon, and vanadium atoms, as well as the CH(2) and C(3)H(3) molecules are considered as illustrative examples. Our result also directly and rigorously connects the ionization potential and electron affinity to the stability of spin states.

Formato

164107 - ?